Question

A mixture contains 9 g of NAOH and H20 each . find mole fraction of Naoh​

Answer 1

Answer:

Mole Fraction

: ∑ᵢ₌₁ᴺnᵢ=nₜₒₜ; ∑ᵢ₌₁ᴺxᵢ=1

Mole fraction of H2O

= No.of moles of H2O/Total No.of moles (H2O + NaOH)

No. of moles of H2O = 36/18 = 2 moles

No. of moles NaOH = 4/40 = 0.1 mol

Total number of moles = 2+0.1 = 2.1

Mole fraction of H2O = 2/2.1 = 0.952

Mole fraction of NaOH = 0.1/2.1 = 0.048

Mass of solution

= Mass of H2O + Mass of NaOH = 36 + 4 = 40 g

Volume of solution = 40/1 = 40 mL

Molarity = No.of moles of solute/Volume of solution in L

= 0.1/0.04L = 2.5M

Explanation:

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