a mixture contains alcohol and water in the ratio 42% of alcohol n water. the % of acohol in new mixture s??
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Suppose the mixture has 12x litres of alcohol and 5x litres of water, then adding 14 litres of water would then result in 5x + 14 litres of water.
As per given information, the new ratio is 4:3
Therefore 12x/(5x+14) = 4/3.
Thus 5x + 14 = 9x and 4x = 14.
Hence x = 3.5 and the amount of alcohol in the mixture is 12x = 12 * 3.5 = 42 litres,
As per given information, the new ratio is 4:3
Therefore 12x/(5x+14) = 4/3.
Thus 5x + 14 = 9x and 4x = 14.
Hence x = 3.5 and the amount of alcohol in the mixture is 12x = 12 * 3.5 = 42 litres,
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