Question

A mixture contains milk and water in the ratio 5:1 . On adding 5 litres of water, the ratio of milk to water becomes 5:2 . Find the quantity of milk in the original mixture.​

Answer 1

Answer:

Step-by-step explanation:

initial quantity of milk =25 lit.

And initial quantity of water= 5 lit.

Answer 2

Given:

The mixture contains milk and water in the ratio 5:1.

On adding 5 litres of water, the ratio of milk to water becomes 5:2.

To find:

The quantity of milk in the original mixture.

Solution:

The mixture contains milk and water in the ratio 5:1.

Let, the common multiple of the ratio be, 'l'.

∴ The amount of milk = (5×l)

                                   = 5l.

∴The amount of water in the mixture = (1×l)

                                                             = l

On adding 5 liters of water in the mixture, the amount of water becomes in the mixture_

(l+5)

= l+5.

On adding 5 litres of water, the ratio of milk to water becomes 5:2 .

∴ According to the problem:

5l : (l+5) = 5:2

$or, \dfrac{5l}{(l+5)} = \dfrac{5}{2}$

or, (5l ×2) = 5(l+5)

or, 10l = 5l + 25

or, (10l-5l) = 25

or, 5l = 25

or, l = (25 ÷5)

or, l = 5 liters.

∴ The amount of milk in the original mixture was _

(5×5)

= 25 liters.

Answer:

            25 liters milk was there in the original mixture.