Question

a mixture contains milk and water in the ratio 8:3 on adding 3 litres of water the ratio becomes 2:1.the quantity of the milk in the mixture is

Answer 1

Answer:

24 litres

Explanation:

Let the initial quantity of mixture be x litres

then,

Milk in the mixture : 8x/11

water in the mixture : 3x/11

A.T.P->

$\frac{8x/11}{(3x/11) + 3} = \frac{2}{1}$

on solving this equation, we get x= 33 l

=> quantity of milk = 8*33/11= 24 l

Answer 2

The quantity of milk in the mixture is 24 litre.

This can be solved as:

Initial ratio of milk and water= 8:3

Final ratio of milk and water= 2:1

Let the initial quantity of milk and water be 8x and 3x.

Now, after addition of 3 litre of water:

Milk= 8x

Water= 3x+3

So the final equation is:

8x/(3x+3) = 2/1

On solving this we get x = 3

So the initial quantities of milk and water are 24 litre and 9 litres respectively.