Math, asked by margarethsailo08, 2 months ago

A mixture contains milk and water in the ratio of 8:7 respectively. 315ml of mixture is taken out and 52ml of water and 88ml of milk is added in the remaining mixture then the ratio of milk to water becomes 4:3 . Find the total quantity of initial mixture​

Answers

Answered by revkori20
0

Answer:

Step-by-step explanation:

Answer the ratio of milk and water in mixture of two milk solution is 18x : 31x. If x is considered as 1 litre than for 18 litre of milk there is 31 litres of water.

Answered by Mithalesh1602398
0

Answer:

The initial quantity of the mixture was 1890 ml.

Step-by-step explanation:

Let's assume that the initial quantity of the mixture is x ml. Then the quantity of milk in the mixture is 8/15 x ml, and the quantity of water is 7/15 x ml.

When 315 ml of the mixture is taken out, the quantity of milk and water that is removed is:

   Milk = 8/15 * 315 ml = 168 ml

   Water = 7/15 * 315 ml = 147 ml

After this, 52 ml of water and 88 ml of milk are added to the remaining mixture. So, the new quantity of milk and water in the mixture becomes:

   Milk = 8/15 x - 168 ml + 88 ml = 8/15 x - 80 ml

  Water = 7/15 x - 147 ml + 52 ml = 7/15 x - 95 ml

According to the problem, the ratio of milk to water in the new mixture is 4:3. Therefore, we have:

   (8/15 x - 80 ml) / (7/15 x - 95 ml) = 4/3

Simplifying the above equation, we get:

   x = 1890 ml

Therefore, the initial quantity of the mixture was 1890 ml.

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