Question

A mixture contains n moles of H2 and 2n moles of CH4. The ratio of C:H atoms in thr mixture id

Answer 1

A mixture contains CH4 and H2 in the ratio 5:1. As we know that 1 mole = 6.022x 10^23 atoms/molecules so n mole of H2 contains 2n mole of H atoms.

Whereas 2n mole of CH4 contains 2xnx4 moles of H-atom and 2n mole of carbon atom so in the resulting mixture total number of H-atoms (8n+2n) = 10n:2n= 5:1.

Answer 2

$\huge \tt 5 \: : \: 1$