Chemistry, asked by sravan17, 1 year ago

a mixture contains N2O4 and and NO2 in the ratio 2:1by volume. the vapour density of the mixture is?

Answers

Answered by Nikhitabisht
52
vapour density N2O4 = molar mass N2O4/molar mass H2 = 92.011/2.016 = 45.64 
vapour density NO2 = molar mass NO2/molar mass H2 = 46.0055/2.016 = 22.82 

The ratio is 2:1 in favor N2O4; therefore, 

v.d. N2O4 x 2 = 91.28 
+ v.d. NO2 x 1 = 22.82 
sum is 114.1 
average is 114.1/3 = 38.033 which rounds to 38.03.

sravan17: why u multiplied 2 and 1?
Nikhitabisht: apply the formula u will understand
sravan17: which formula
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