Question

A mixture contains nuts and screws in the ratio 4:3 . If 7screws are added to mixture the ratio becomes 3:4. Find the number of nuts in the mixture.​

Answer 1

Given:

A mixture contains nuts and screws in the ratio 4:3. If 7screws are added to the mixture the ratio becomes 3:4. Find the number of nuts in the mixture.​

To find:

Find the number of nuts in the mixture.​

Solution:

The ratio of nuts and screw is 4:3

So, let's say,

"4x" → no. of nuts

"3x" → no. of screws

After adding 7 screws, the no. of screws now becomes = 3x + 7

The new ratio of nuts and screws becomes 3:4

As per the question, we can form the equation as,

$\frac{4x}{3x\: +\: 7} = \frac{3}{4}$

$\implies 4 \times 4x = 3(3x+ 7)$

$\implies 16x = 9x+ 21$

$\implies 16x - 9x = 21$

$\implies 7x = 21$

$\implies \bold{x = 3}$

∴ No. of nuts in the mixture = 4x = 4 × 3 = 12

Thus, the number of nuts in the mixture is → 12.

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