A mixture contains rice flour and corn in the ratio of 5:9:2. If the mixture weighs
800 grams, find the percentage of rice, flour and corn in the mixture.
Answers
Answered by
10
Answer:
5x+9x+2x=800
Explanation:
x=800/16
x=50
rice 250gms
flour 450gms
corn 100gms
percentenges are 31.25,56.25,12.5 for rice, flour, corn
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Answered by
9
Answer:
Rice = 5x
Flour = 9x
Corn = 2x
So,
5x + 9x + 2x = 800
16x = 800
x = 800/16 = 50
Rice = 5x = 5 × 50 = 250
Flour = 9x = 9 × 50 = 450
Corn = 2x = 2 × 50 = 100
So in % =
Rice = 250/800 × 100 = 31.25%
Flour = 450/800 × 100 = 56.25%
Corn = 100/800 × 100 = 12.5%
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