a mixture contains two components A and B the solubilities of A and B in water near its boliling point are 10g per 100 ml and 2g per 100 ml respectivly . how will you seprate A and B frombthis mixture
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Explanation:
A = 10g/100ml = 1g/10ml
B = 2g/100ml= 1g/50ml
You can easily separate these mixtures by first separatedly boiling 10 ml of water at 100d C
Therefore you will get 1gm of A
and 0.02gms of B
Hope it helps '
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