Question

a mixture contains two components A and B the solubilities of A and B in water near its boliling point are 10g per 100 ml and 2g per 100 ml respectivly . how will you seprate A and B frombthis mixture ​

Answer 1

Answer:

Here you go bro

Explanation:

A =  10g/100ml = 1g/10ml

B = 2g/100ml= 1g/50ml

You can easily separate these mixtures by first separatedly boiling 10 ml of water at 100d C

Therefore you will get 1gm of A

and 0.02gms of B

Hope it helps '

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