A mixture Contains X litre milk And Y litre Water. If 18Litre of mixture is taken out and replaced with water such that ratio of milk and water becomes 3:1 But If 60 Litre of mixture is taken out and replaced with water then ratio of milk and water becomes 2:3. Find X?
Answers
Given : A mixture Contains X litre milk And Y litre Water . 18Litre of mixture is taken out and replaced with water ratio of milk and water becomes 3:1 .
To find : Value of X
Solution:
Milk = X litre
Water = Y Litre
Total = X + Y litre
18 litre of mixture is taken out and replaced with Water
=> Milk = X - 18X/(X + Y)
=> Water = Y - 18Y/(X + Y) + 18
ratio of milk and water becomes 3:1
=> (X - 18X/(X + Y) ) / ( Y - 18Y/(X + Y) + 18) = 3/1
=> X - 18X/(X + Y) = 3Y - 54Y/(X + Y) + 54
=> X² + XY - 18X = 3XY + 3Y² - 54Y + 54X + 54Y
=> X ² - 3Y² = 2XY + 72X
if 60 litre of mixture is taken out and replaced with Water
=> Milk = X - 60X/(X + Y)
=> Water = Y -60Y/(X + Y) + 60
ratio of milk and water becomes 3:1
=> (X - 60X/(X + Y) ) / ( Y - 60Y/(X + Y) + 60) = 2/3
=> 3X - 180X/(X + Y) = 2Y - 120Y/(X + Y) + 120
=> 3X² + 3XY - 180X = 2XY + 2Y² - 120Y + 120X + 120Y
=> 3X ² - 2Y² = -XY + 300X
X ² -3Y² = 2XY + 72X
=> 2X² - 6Y² = 4XY + 144X
3X ² - 2Y² = -XY + 300X
=> 9X ² - 6Y² = -3XY + 900X
=> 7X² = -7XY + 756X
=> X = Y + 108
=> X + Y = 108
X ² - 3Y² = 2XY + 72X
=> X² - 3(108 - X)² = 2X(108 - X) + 72X
=> X² - 3X² - 3* 108² +3 *216X = 216X - 2X² + 72X
=> 360X = 3* 108²
=> X = 97.2
Total Milk Water
108 Litre 97.2 Litre 10.8 Litre
108 81 27
108 43.2 64.8
X = 97.2
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Answer. 97.2L
Step by-step explanation:
here 3:1 ratio means 75%
and 2:3 means 40% concentration
difference in water added is (60-18)L and
percentage is (75-40)%
i.e 42L give 35%
or 5% given by 6L
then 40% by 48L
now look at condition 2:3 or 40% concentration
here 48L was added to get 40%
so total quantity will be 48 + 60 =108L
in 3:1 ratio is 81L and 27L
on removing 18L
81 : 9
i.e initial ratio was 9:1
hence X= (108/10)x9 = 97.2L