Question

A mixture has four components p, q, r and s if 0.2 mol of each component is present in the mixture the total sum of mole fraction of all components is

Answer 1

Answer:

ofc 1 is the actual ans

Explanation:

hope it helps u

Answer 2

Answer:

The total sum all the components p, q, r and s in the mixture is equal to one.

Explanation:

Given: number of moles of p, $n_{p}=0.2mol$

number of moles of q, $n_{q}=0.2moles$

number of moles of r, $n_{r}=0.2moles$

number of moles of s, $n_{s}=0.2moles$

Mole fraction of component p, $x_{p}=\frac{n_{p}}{n_{p}+n_{q}+n_{r}+n_{s}}$

  $x_{p}=\frac{0.2}{0.2+0.2+0.2+0.2}=\frac{0.2}{0.8}=0.25$

similarly, Mole fraction of component q, $x_{q}=\frac{n_{q}}{n_{p}+n_{q}+n_{r}+n_{s}}=\frac{0.2}{0.8}=0.25$

 Mole fraction of r, $x_{r}=\frac{n_{r}}{n_{p}+n_{q}+n_{r}+n_{s}}=\frac{0.2}{0.8}=0.25$

Mole fraction of s, $x_{s}=\frac{n_{s}}{n_{p}+n_{q}+n_{r}+n_{s}}=\frac{0.2}{0.8}=0.25$

Sum of mole fraction of all components $=x_{p}+x_{q}+x_{r}+x_{s}$

                                                   $=0.25+0.25+0.25+0.25$

Therefore,   $x_{p}+x_{q}+x_{r}+x_{s}=1$