Math, asked by himanshurohilla7771, 10 months ago

A mixture is made out of a composition of three liquids in 5:6:9. The cost price of the three liquids were Rs. 56, Rs. 78 and Rs. 92. What would be the selling price of the final mixture if it is being sold at 15% profit ?

Answers

Answered by bhagyashreechowdhury
0

Answer:

The composition of three liquids = 5 : 6 : 9

C.P. of 3 liquids is Rs. 56, Rs. 78 & Rs. 92 respectively.

Total Cost Price of the mixture is,

= (5 * 56) + (6 * 78) + (9 * 92)  

= 280 + 468 + 828  

= Rs. 1576  

Profit% = 15%

Therefore,  

S.P. of the final mixture is,

= C.P. * [(100+G%)/100]  

= 1576 * [(100+15)/100]

= Rs. 1812.4

Answered by nath27076
0

Answer: The SP of the final mixture sold at 15% profit would be ₹ 1812.40

Step-by-step explanation: In the mixture of the liquids, it is mentioned that the cost price of the liquid present in ratio 5 was ₹ 56, and that for ratio 6 was ₹ 78 and for ratio 9 was ₹ 92.

Thus, in the mixture, the total cost price (CP) of the entire liquid would be,

(5*56) + (6*78) + (9*92)

= 280 + 468 + 828 = ₹ 1576.

The formula we require for calculating the Selling price in this question is:

Profit Percentage = \frac{SP - CP}{CP} * 100

Here, let us consider the Selling Price (SP) = x

According to question, profit % = 15 %

CP = ₹ 1576

15 = \frac{x - 1576}{1576} * 100

\frac{15 * 1576}{100} = x - 1576

\frac{23640}{100} = x - 1576

x = 236.40 + 1576

x = 1812.40

Thus, the SP of the mixture will be ₹ 1812.40

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