, a mixture of 1.65 into 10 raise to 21 molecules of x and 1.85 into 10 raise to 21 molecules of virus 0.688 gram the molar weight of x is assume all weight of why is 187
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Molecular weight = Vapour density x 2 (For gases only) 10. ..... 5x0.0821x3 p x 10~3 = 6.023 x l O 2 3 P — 2.04 x 10~21 atm Solution 9. ..... Find the temperature assuming the thermal expansion of mercury to be ...... A mixture of 1.65 x 1021 molecules of x and 1.85 x 1021 moleculesof y weigh 0.688 g.
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