a mixture of 1 mole of N2 and 3 moles of H2 is allowed to react at a constant pressure of 100 bar . at equilibrium 0.6 moles of NH3 is formed . calculate equilibrium constant for a reaction. N2 + H2 ------ NH3
i couldn't give the ans for some reason so here it is
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Answer:
Volume = 1 L
Temperature = 400 K
Equilibrium constant, K
c
=
27
4
The Net balanced chemical reaction is,
N
2
+3H
2
→2NH
3
Initial concentration 1 2 0
At equilibrium (1-x) (3-3x) 2x
The expression for equilibrium constant is,
K
c
=
[N
2
][H
2
]
3
[NH
3
]
2
By rearranging the terms, we get the value of x.
x=0.381 mole/L
The concentration of NH
3
at equilibrium = 2x =2×0.381=0.762mole/L
Similar questions
Volume = 1 L
Temperature = 400 K
Equilibrium constant, Kc=274
The Net balanced chemical reaction is,
N2+3H2→2NH3
Initial concentration 1 2 0
At equilibrium (1-x) (3-3x) 2x
The expression for equilibrium constant is,
Kc=[N2][H2]3[NH3]2
By rearranging the terms, we get the value of x.
x=0.381 mole/L
The concentration of NH3 at equilibrium = 2x =2×0.381=0.762mole/L