Question

A mixture of 160 gallons of wine and water contains
25% water. How much water must be added to the
mixture in order to increase the percentage of water
to 40% of the new mixture?
(a) 40 gals
(b) 50 gals
(c) 80 gals
(d) 33 gals​

Answer 1

Given,

Total volume of the initial mixture = 160 gallons

The water percentage = 25%

To find,

The amount of water that we have to add to make 40% water in the new mixture.

Solution,

We can simply solve this mathematical problem by using the following mathematical process.

Wine percentage in the Initial mixture = 100%-25% = 75%

Wine amount in the initial mixture = 160 × 75/100 = 120 gallons

Water amount = 160-120 = 40 gallons

Let, we have to add x gallons of water

New water amount = 40+x gallons

Total mixture amount = 160+x gallons

Water percentage = 100 × (40+x)/(160+x) gallons

According to the data mentioned in the question,

100 × (40+x)/(160+x) = 40

(4000+100x)/(160+x) = 40

4000+100x = 6400 + 40x

100x-40x = 6400-4000

60x = 2400

x = 40

Hence, we have to add 40 gallons of water.