A mixture of 2.3 g formic acid and 4.5 oxalic acid is treated with conc.H2SO4 . The evolved gaseous mixture is passed through KOH pallets . Weight in (g) of the remaining product at STP will be
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Answer:
2.8g
Explanation:
HCOOH → CO+H2O
(moles)i = 2.346 = 1/20 0 0
(moles)i = 0 1/20 1/20
H2C2O4 H2SO4 → CO+CO2+H2O
(moles)i = 4.5/90 =1/20 0 0 0
(moles)i = 0 1/20 1/20 1/20
CO2 is absorbed by KOH
Thus, the remaining product will be only CO
Moles of CO formed from both reactions -
= 1/20 + 1/20 = 110
Left mass of CO = moles × molar mass
= 1/10×28
= 2.8g
Thus, the remaining weight will be 2.8g
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