a mixture of 2.3 gram formic acid and 4.5 gram oxalic acid is treated with concentrated H2 s o4 .the evolved gaseous mixture is passed through KOH pellet weight of the remaining product at STP will be .
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Answer:
The answer is 2.8g
Explanation:
The chemical reaction of oxalic acid:
HCOOH ------> CO + H2O
Calculate the moles of carbon monoxide formed.
Moles of CO = mass of formic acid/molar mass of formic acid
= 2.3 / 46 = 23 /460
= 1/20 moles = 0.05 moles
Calculate the moles of carbon monoxide formed in the presence of dilute H2SO4.
H2C2O4 ------> CO + CO2 + H2O
Moles of CO = 4.5 / 90 = 45 / 900
= 1/ 20 = 0.05 moles
The only product formed is CO because KOH absorbs CO2.
The total number of moles formed during each reaction.
0.05 + 0.05 = 0.1 moles
Mass of CO = no. of moles x molar mass
= 0.1 x 28
= 2.8 g
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