a mixture of 2.3 gram formic acid and 4.5 gram oxalic acid is treated with concentrated H2 s o4
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HCOOH⟶CO+H2OHCOOH⟶CO+H2O(moles)i=2.346=12000(moles)i=2.346=12000(moles)i=0120120(moles)i=0120120H2C2O4H2SO4−→−−−CO+CO2+H2OH2C2O4H2SO4→CO+CO2+H2O(moles)i=4.590=120000(moles)i=4.590=120000(moles)i=0120120120(moles)i=0120120120CO2CO2 is absorbed by KOHKOHSo the remaining product is only COMoles of CO formed from both reactions.=120+120=110=120+120=110Left mass of CO=moles×molarmassCO=moles×molarmass=110=110×28×28=2.8g
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