A mixture of 2 liquids , hydrazine n2h5 and n2o4 are used in rockets. they produce n2 and water vapors .how many grams of n2 gas will be formed by reacting 100 gram of n2h4 and 200 gram of n2 o4
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Answer:
Moles:
n
N
2
H
4
=0.705 moles
n
H
2
O
=
34
17
=0.5 moles
1 moles N
2
H
4
required 2 moles H
2
O
2
∴0.705 moles N
2
H
4
requires 1.41 moles H
2
O
2
But we have only 0.5 moles H
2
O
2
∴N
2
H
4
will be leftover and it is our excess reagent.
2 mole H
2
O
2
use 1 mole N
2
H
4
∴0.5 moles H
2
O
2
will need x moles N
2
H
4
x=
2
1×0.5
=0.25 moles
∴N
2
H
4
left unused =0.705−0.25=0.455 moles
Mass of N
2
H
4
left unreacted =0.455×32=14.6 g
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