a mixture of 2 moles of n2 and 8moles of h2 are heated in a closed vessel till equillibrium is established at equillibrium 0.4moles of N2 was present the equillibrium concentration of h2 will be
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Answer:
Explanation:
H
2
+3H
2
⇌2NH
3
t=0 2 8 −
t eg. 2.x 8−3x 2x
2−x=0.4
⇒x=1.6 ∴(H
2
)
eq
=8−4.8=3.2
[H
2
]
eq
=
2
3.2
=1.6mol/lit
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