a mixture of 20 litres contains milk and water in the ratio 4:1. How many litre of the mixture be taken out and the same quantity of water added to it so that the ratio of milk and water becomes 3:2?
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Answered by
7
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Milk in container earlier=(4/5)*45=36 L
Water in container earlier=(1/5)*45=9 L
Now required milk:water ratio=3:2
Suppose we add x L of water in container,then;
36/(9+x)=3:2
solving we get x=15 L
Therefore 15 L of water required to make ratio 3:2
So on adding 15 liters water to the mixture of 45 liters and making it's final Volume to 60 liters will give a milk to water mixture in the ratio 3 : 2 . OK .
__________________________
__________________________
The answer of u r question is..✌️✌️
Milk in container earlier=(4/5)*45=36 L
Water in container earlier=(1/5)*45=9 L
Now required milk:water ratio=3:2
Suppose we add x L of water in container,then;
36/(9+x)=3:2
solving we get x=15 L
Therefore 15 L of water required to make ratio 3:2
So on adding 15 liters water to the mixture of 45 liters and making it's final Volume to 60 liters will give a milk to water mixture in the ratio 3 : 2 . OK .
Answered by
9
Answer:
Step-by-step explanation:
Mixture से जो भी निकलेगा उसमे milk and water का ratio 4:1 ही होगा ।
4y + 1y निकाला = 5y
अब बचा हुआ milk = 16 - 4y
बचा हुआ water = 4 - 1y +5y
Then equation is,
16-4y / 4-1y+5y = 3/2
32-8y = 12-3y+15y
32-12 = -3y+15y+8y
20 = 20y
20/20 = y
1 = y
Water निकाला = 5y
= 5×1
= 5 liters
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