A mixture of 250g of ice at 0c is kept in a calorimetre
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Hey friend,
Here is your answer:
Given that:
10 gm of ice at 0°C is kept in calorimeter of water 10 gm.
To find,
The amount of heat that must be supplied.
Solution:
First we must calculate the energy needed for ice at 0°C to Convert into water at same temperature.
So, We know that,
Here , L v - Latent Heat of Fusion of water = 80 cal/gm
⇒
Now it has to convert from 0°C water to 100°C of water.
Then,
⇒
Here , S- Specific Heat of water = (1 cal /gm k) , And Change in temperature is (T f) - (T i)
Then,
⇒
Now, From 100°C water to Vapor at same temperature.
Here Lv = 540 cal/gm.
⇒
Then,
⇒
⇒
_____________________________________________________
Hope my answer is helpful to you.
Here is your answer:
Given that:
10 gm of ice at 0°C is kept in calorimeter of water 10 gm.
To find,
The amount of heat that must be supplied.
Solution:
First we must calculate the energy needed for ice at 0°C to Convert into water at same temperature.
So, We know that,
Here , L v - Latent Heat of Fusion of water = 80 cal/gm
⇒
Now it has to convert from 0°C water to 100°C of water.
Then,
⇒
Here , S- Specific Heat of water = (1 cal /gm k) , And Change in temperature is (T f) - (T i)
Then,
⇒
Now, From 100°C water to Vapor at same temperature.
Here Lv = 540 cal/gm.
⇒
Then,
⇒
⇒
_____________________________________________________
Hope my answer is helpful to you.
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