Chemistry, asked by OmDeore, 1 year ago

a mixture of 2g of hydrogen and 32g of oxygen will occupy howuch volume at ntp

Answers

Answered by sahaj05

3

Explanation:

2g of H2 = 1 mole of H2

32g of O2 = 1 mole of O2

Total moles = 2

Volume = moles x 22.4
Volume = 2 x 22.4 = 44.8 lit at ntp

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