A mixture of 40 litres of milk and water contains
10%water. How much water should be added to
it so that water may be 20% in new mixture?
1. 2.5 ltr 2. 3.5 ltr 3. 4 Itr 4. 5 ltr
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Total volume of mixture = 40L
water = 10% of 40 L = 4 L
Let the water added be x L.
So that the total water content now becomes (4+x) L
After adding water ---
Total Volume of mixture = (40+x) L
but water is now, 20% of total
=> water = 20% of (40+x)
=> water = (8+0.2x) L
but from earlier we know water is (4+x) L
therefore, (8+0.2x) = (4+x)
=> 8-4 = x-0.2x
=> x = 5 L
Hence the answer is 5 L water must be added.
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