Question

A mixture of 40

litres of milk and water contains 10%

water. How much water should be

added to it so

that water may be 20% in the new

mixture?​

Answer 1

given,

in 40lits 10% of water is present

so there is 4 lits of water

suppose if add x lits of water to the mixture

total amount = 40+x liters

according to the question,

((40+x)20)/100 = 4+x

(40+x)/5 = 4+x

40+x = 20+5x

20 = 4x

x = 5

so we need to add 5lit of water to mixture

Answer 2

Answer:

mixture=40L

water contain=10%of 40L=4L

milk contain=40-4=36L

New ratio should be water=20%

                                   milk=80% ie milk:water=4:1

let x be the amount of water to be added then total water=x+4

now, 36/(x+4)=4/1=5L

Step-by-step explanation: