A mixture of 45 L of spirit & water contain 20% water in it . How much water much be added to it to make water 25% in new mixture ?
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Solution :
water in original solution = 0.2(45) = 9 L
spirit in original solution = 36 L
let the new mix be x L
x = 36 + 0.25(x)
0.75x = 36
x = 48
so new mix is 48 L
with 36 L of spirit and 12 L of water
Hope that helps
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water in original solution = 0.2(45) = 9 L
spirit in original solution = 36 L
let the new mix be x L
x = 36 + 0.25(x)
0.75x = 36
x = 48
so new mix is 48 L
with 36 L of spirit and 12 L of water
Hope that helps
please mark my answer as Brainliest..
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