Question

A mixture of 66 litres contains whisky and water in the ratio
4:7 how many litres of whisky and water each must be added
to the mixture to make the ratio 2:3?

Answer 1

$\bold {\huge {Solutions:-}}$

We have,

Mixture of whiskey and water = 66 liters

Initial ratio of whiskey and water = 4:7

Changed ratio of whiskey and water = 2:3

Let the whiskey be 4x
and water be 7x

A/q

4x+7x = 66
=> 11x = 66
=> x = 66/11 = 6

Whisky = 4×6 = 24 litres
Water = 7×6 = 42 litres

Now,

4+x/7+x = 2/3

=> 3(4+x) = 2(7+x)

=> 12 + 3x = 14 + 2x

=> 3x - 2x = 14 - 12

=> x = 2

Then,

Whisky = 4+x = 4+2 = 6

Water = 7+x = 7+2 = 9

So,
Whiskey = 6 × 6 = 36 litres
Water = 9×6 = 54 litres

Hence,

Initial weight of whiskey = 24 litres
Changed Weight of whiskey = 36 litres

$\underline {\bold {Added~whiskey~= 36 - 24~=~12~L}}$

Initial weight of water = 42 litres
Changed Weight of water = 54 litres

$\bold {\underline {Added~water~=~54 - 42~=~12~L}}$

Answer 2

❤❤Here is your answer ✌ ✌

$\huge\boxed{\red{\bold{Answer}}}$

$<b>$

$\huge\underline{\purple{\bold{Given}}}$

Mixture of whiskey & water ➡66 liters↩

Initial ratio of whiskey & water ➡4:7

Changed ratio of whiskey & water ➡2:3

Let,
The whiskey be 4x & water be 7x

A/q

➡4x+7x = 66
➡11x = 66
➡x = 66/11 = 6

Whisky➡ 4×6➡24 litres•
Water➡7×6➡42 litres•

now here

➡4+x/7+x = 2/3

➡ 3(4+x) = 2(7+x)

➡12 + 3x = 14 + 2x

➡3x - 2x = 14 - 12

➡x = 2

Again

Whisky➡4+x = 4+2 = 6

Water➡7+x = 7+2 = 9

So,hence

Whiskey➡6 × 6 = 36 litres•
Water➡9×6 = 54 litres•

Hence, 

Initial weight of whiskey = 24 litres•

Changed Weight of whiskey = 36 litres•

$\huge\underline{\green{\bold{Now}}}$

Added whiskey = 36 - 24 =12 L↩

Added whiskey =36−24 = 12 L​↩

Initial weight of water = 42 litres↩

Changed Weight of water = 54 litres↩

Added water = 54−42 = 12 L​itres↩