Question

a mixture of 80 litres of acid and water contains 20 litres of acid . what percentof water is in the mixture?​

Answer 1

Water = 60 l

Percentage = 60 / 80 * 100

= 75%

Answer 2

Mass of solution = 80 litres

Mass of Acid = 20 litres

Mass of water = Mass of solution - Acid

= 80-20

= 60 litres

Now , Percentage of water =( Mass of water ÷ Mass of solution ) × 100

=( 60÷80) × 100

=0.75 ×100

= 75%

.•. the percentage of water in the solution is 75% ,i.e., The acid is dilute.

hope it helps