Chemistry, asked by Vamsi9851, 19 days ago

A mixture of an organic liquid a and water distilled under one atmospheric pressure at 99.2 how many grams of steam

Answers

Answered by ranafathima201011
0

Answer:

5.15g.

Explanation:

Partial pressure of A=760-739=21mmHg. Mass of steam condensed per g of liquid A=17.53.399=5.15g.

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Answered by sainnirmit
0

Explanation:

Total pressure of the solution(A+Water)=1 atm=760mm Hg

Vapour pressure of water=739mm Hg

Vapour pressure of organic liquid A is=760−739=21mm Hg

Moleucular mass of A=123

WwaterWA=PB×MMwaterPA×MMA

Where WA &Wwater represents the mass of organic liquid A and mass of water respectively.

MMA &MMwater represents the molar mass of A and molar mass of water respectively

Wwater1=739×1821×123=5.19 g

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