Question

a mixture of c2h4 and co2 effuses four times slowely as H2 under identical condition of temperature and pressure.the molar ratio of C2H4 to CO2 in the mixture is.
1)1:1
2)2:1
3)3:1
4)3:2​

Answer 1

answer : option (2) 2 : 1

explanation : first, find molecular weight of mixture of C2H4 and CO2.

according to Graham's law of diffusion of gas under similar conditions of temperature and pressure,

rate of diffusion ∝ 1/√(molecular weight)

so, r1/r2 = √{M2/M1}

here, r1 represents rate of diffusion of mixture and r2 represents rate of diffusion of H2.

given, r1/r2 = 1/4

M2 = 2 g/mol [ as molecular weight of hydrogen, H2 is 2g/mol]

now, 1/4 = √{2/M1}

or, M2 = 32g/mol.

now, let x : y is molar ratio of C2H4 and CO2 respectively.

so, molecular weight = (x × 26 + y × 44)/(x + y)

or, 32 = (26x + 44y)/(x + y)

or, 32x + 32y = 26x + 44y

or, 6x = 12y

or, x = 2y

or, x/y = 2/1

hence,molar ratio is 2 : 1

Answer 2

Answer:option 3

Explanation: