A mixture of C2H4,CO,N2 gases having total pressure 250mm of Hg in which 250mm Hg of O2 is added at 27°C and then sparked.After the system is brought to its original temperature total pressure becomes 370mm Hg.If partial pressure of CO2 is 200mm Hg then calculate initial partial pressure of C2H4
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The partial pressure of C2H4 is equal to 50 mmHg .
Explanation:
- Let's suppose the three gases are x,y, and z respectively.
- x + y + z = 250 mmHg
- The equation is
- C2H4 + 3 O2 ------> 2CO2 + 2H2O
- (2x + y) + z + [ 250 - (3x + y / 2) + 20 = 370
The equation for carbon dioxide gas is
CO + O2 -----> CO2
- x + y / 2 + z = 100
2x + y = 200
From equation (i), (ii) and (iii) we can conclude that
x = 50, y =100 and z = 100
The partial pressure of C2H4 = 50 mmHg
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