A mixture of C2H5OH & water contains 54% water by weight. Calculate the mole fraction of alcohol & Water in this mixture ?
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Assume 100 g of the mixture are present.
Mass of water and methanol are 54 g and 46 g respectively.
The number of moles of water are 1854=3
The number of moles of ethanol are 4646=1
The mole fraction of ethanol is 1+31=0.25
So, 100x= 25
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