Question

A mixture of C5H8 and H2, gas was placed in a
container at a constant temperature. Initial volume
of mixture was 10 ml. Sparking the mixture caused
hydrogenation reaction
C5H8 (g) + 2H2 = C5H12(g)
Causing a volume decreases by 6 ml. Excess of
was then added and on sparking the volume further
decreased by 15 ml. Calculate
I) Volume of each gas in original mixture
ii) Mole fraction of CH in original mixture​

Answer 1

Answer:

C5H8(g)+2H2(g)→C5H12(g)