Question

a mixture of ch4 and c2h6 has an average molecular weight of 22.4. find mole % ch4 and c2h6 in the mixture.​

Answer 1

Answer:

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Explanation:

Suppose we take 1 mole of CH4 Weight=16gm

And 1mole C2H6 weight =30gm

Now, 1 mole of both CH4 and C2H6 occupy 22.4L

Therefore when mixed Total weight of mixture=16+30=46

Total volume of mixture=22.4+22.4=44.8L 44.8L of mixture weigh 46g So,2.24L of mixture weighs=( 46÷44.8)×2.24=2.3g