a mixture of CS2 and H2S when oxidized earrings a mixture of Co2 and SO2 and H2O which exerts a pressure of 740 8.8 mm of HG when connected in 60 litres vessel at 3 27 degree Celsius to oxidized Asher 2 and the mixture 700 ml of 2 and iodide where required what was the mole fraction of CS in the mixture
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Answer:
hii mate here is your answer
Explanation:
According to question ,
CS
2
+3O
2
→CO
2
+2SO
2
__________(1)
2H
2
S+3O
2
→2H
2
O+2SO
2
____________(2)
Total moles of gases SO
2
,CO
2
and H
2
O exerted.
pressure,
n=
RT
PV
=
0.0821×600
7.2×82.1
n=
49.26
591.12
= 12 moles.
when I
2
react with SO
2
I
2
+SO
2
+2H
2
O→2HI+H
2
SO
4
moles of I
2
req. = 5×2 = 10
It means only 10 mole SO
2
released
and 12-10=2 moles other gases (CO
2
,H
2
O)
According to eq (1) and (2).
2 mole SO
2
= 1 mole CS
2
10 mole SO
2
=
2
10
= 5 mole CS
2
Rest 2 mole gas also given by 2 mole CS
2
So,
Total moles of CS
2
in mixture = 5 + 2 = 7
Answer = 7
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