Chemistry, asked by rroy02631, 21 days ago

a mixture of CS2 and H2S when oxidized earrings a mixture of Co2 and SO2 and H2O which exerts a pressure of 740 8.8 mm of HG when connected in 60 litres vessel at 3 27 degree Celsius to oxidized Asher 2 and the mixture 700 ml of 2 and iodide where required what was the mole fraction of CS in the mixture​

Answers

Answered by piyushnath005
0

Answer:

hii mate here is your answer

Explanation:

According to question ,

CS

2

+3O

2

→CO

2

+2SO

2

__________(1)

2H

2

S+3O

2

→2H

2

O+2SO

2

____________(2)

Total moles of gases SO

2

,CO

2

and H

2

O exerted.

pressure,

n=

RT

PV

=

0.0821×600

7.2×82.1

n=

49.26

591.12

= 12 moles.

when I

2

react with SO

2

I

2

+SO

2

+2H

2

O→2HI+H

2

SO

4

moles of I

2

req. = 5×2 = 10

It means only 10 mole SO

2

released

and 12-10=2 moles other gases (CO

2

,H

2

O)

According to eq (1) and (2).

2 mole SO

2

= 1 mole CS

2

10 mole SO

2

=

2

10

= 5 mole CS

2

Rest 2 mole gas also given by 2 mole CS

2

So,

Total moles of CS

2

in mixture = 5 + 2 = 7

Answer = 7

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