a mixture of dettol and water contains 80% water.what volume of dettol is to be added to 60 ltrs of this mixture .so that the new mixer of contains is 75% water.
Answers
Answered by
4
Step-by-step explanation:
volume of detail should be added is 5ltrs
Answered by
11
Answer:
4 lit.
Step-by-step explanation:
In 60 lt mixture 80% water,then water =
(60*80)/100
=48 lt
so dettol is 60-48=12 lt
let dettol to be added in the mixture is 'x'
new mixture=(60+x) lt
and in new mixture dettol is (12+x) lt
in the question it is given that in the new mixture 75% is water,so dettol is (100-75)%=25%
so,
(60+x)*25/100=(12+x)
or,60+x=48+4x
or,3x= 12
or,x = 4
so,4 lt dettol is to be added.
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