Math, asked by ghoruibonolota, 7 months ago

a mixture of dettol and water contains 80% water.what volume of dettol is to be added to 60 ltrs of this mixture .so that the new mixer of contains is 75% water.​

Answers

Answered by manikanta1126
4

Step-by-step explanation:

volume of detail should be added is 5ltrs

Answered by jgecevan
11

Answer:

4 lit.

Step-by-step explanation:

In 60 lt mixture 80% water,then water =

(60*80)/100

=48 lt

so dettol is 60-48=12 lt

let dettol to be added in the mixture is 'x'

new mixture=(60+x) lt

and in new mixture dettol is (12+x) lt

in the question it is given that in the new mixture 75% is water,so dettol is (100-75)%=25%

so,

(60+x)*25/100=(12+x)

or,60+x=48+4x

or,3x= 12

or,x = 4

so,4 lt dettol is to be added.

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