Question

A mixture of dihydrogen and dioxygen at 1 bar pressure contains 20% by weight of dihydrogen. Calculate the partial pressure of dihydrogen.

Answer 1

Hii dear!!
A mixture of H2 &O2 contains 20% by weight of H2.

Let weight of mixture is 100g
Let, weight of H2 = 20g
mole of H2 = Given weight / molar weight
=20 / 2 = 10 mol
weight of O2 = 80g
mole of O2 = Given weight / molar weight
80 / 33 = 2.5 mol

Now, mole fraction of H2 (x) = mole of H2 {mole of H2 + mole of O2 }
= 10 / (10 + 2.5)
= 10 / 12.5 = 0.8

Now, particle pressure of H2 = mole fraction of H2 * total pressure

A / C to question
total pressure = 1 bar

Now, particle pressure = 0.8 * 1 = 0.8 bar.

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