Question

A mixture of gases at 760 torr contains 55% nitrogen,25% oxygen, and 20% co2 by mole.what is partial pressure of each gas

Answer 1

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Answer 2

Answer : The partial pressure of nitrogen, oxygen and carbon dioxide are, 418 torr, 190 torr and 152 torr.

Solution : Given,

Total pressure of gas = 760 torr

Moles of nitrogen = 0.55 moles

Moles of oxygen = 0.25 moles

Moles of carbon dioxide = 0.20 moles

Total number of moles = 0.55 + 0.25 + 0.20 = 1

Formula used for mole fraction : $\text{Mole fraction}=\frac{\text{Moles of gas}}{\text{Total number of moles}}$

Mole fraction of nitrogen = 0.55

Mole fraction of oxygen = 0.25

Mole fraction of carbon dioxide = 0.20

Now we have to calculate the partial pressure of each gas.

$p^o_{N_2}=X_{N_2}\times P_T=0.55\times 760torr=418torr$

$p^o_{O_2}=X_{O_2}\times P_T=0.25\times 760torr=190torr$

$p^o_{CO_2}=X_{CO_2}\times P_T=0.20\times 760torr=152torr$

Therefore, the partial pressure of nitrogen, oxygen and carbon dioxide are, 418 torr, 190 torr and 152 torr.