Question

A mixture of H and 12 (vapour) in molecular proportion of 2:3 was heated at 440°C till the reaction
H2 + 12 + 2HI reached equilibrium state calculate the percentage of lodine converted in to product
(ke at 440°C = 0.02)
(A) 16.15%
(B) 35.38%
(C) 26.17%
(D) 5.38%​

Answer 1

Explanation:

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