A mixture of He, Ne, and Ar has a pressure of 7.85 bar. If the Ne has a mole fraction of 0.47 and Ar has a mole fraction of 0.23, what is the pressure of He?
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A mixture of He, Ne and Ar has a pressure of 7.85 atm. If the Ne has a mole fraction of 0.47 and Ar has a mole fraction of 0.23, what is the pressure of He? A) 4.2atm B) 3.7 atm C )1.8 atm D) 5.5 atm E 2.4 atm
Chemistry
1 Answer
anor277
Mar 27, 2018
Option E
Explanation:
You got a three component mix....the sum of the molar fractions MUST add up to ONE....
And so
χ
H
e
=
1
−
χ
N
e
−
χ
A
r
=
1
−
0.47
−
0.23
=
0.30
...
And since the mole fraction is directly proportional to the total pressure....
P
H
e
=
χ
O
2
×
P
total
=
0.30
×
7.85
⋅
a
t
m
≡
2.355
⋅
a
t
m
...
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