A mixture of hydrazine and H2O2 with Cu(ii) catalyst used as a rocket propellant. Why????
please don't copied answer from google please give me correct answer
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For starters, you know by looking at the balanced chemical equation
N2H4(l)+2H2O2(l)→N2(g)+4H2O(g)
that every mole of hydrazine that takes part in the reaction consumes 2 moles of hydrogen peroxide. In other words, the two reactants take part in the reaction in a 1:2 mole ratio.
You already know that the reaction consumed 0.453 moles of hydrogen peroxide, so use this mole ratio to figure out how many moles of hydrazine reacted
0.453moles H2O2⋅1 mole N2H42moles H2O2=0.2265 moles N2H4
To convert this to grams, use the molar mass of hydrazine
0.2265moles N2H4⋅32.045 g1mole N2H4=7.26 g−−−−−
The answer is rounded to three sig figs, the number of sig figs you have for the number of moles of hydrogen peroxide.
N2H4(l)+2H2O2(l)→N2(g)+4H2O(g)
that every mole of hydrazine that takes part in the reaction consumes 2 moles of hydrogen peroxide. In other words, the two reactants take part in the reaction in a 1:2 mole ratio.
You already know that the reaction consumed 0.453 moles of hydrogen peroxide, so use this mole ratio to figure out how many moles of hydrazine reacted
0.453moles H2O2⋅1 mole N2H42moles H2O2=0.2265 moles N2H4
To convert this to grams, use the molar mass of hydrazine
0.2265moles N2H4⋅32.045 g1mole N2H4=7.26 g−−−−−
The answer is rounded to three sig figs, the number of sig figs you have for the number of moles of hydrogen peroxide.
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