Question

a mixture of hydrogen and oxygen contains 11.1 % hydrogen by weight calculate the average molecular weight of gas mixture and the partial pressure of Oxygen and hydrogen at 100 kpa and 303K​

Answer 1

Answer:

As the mixture contains 20% by weight of hydrogen means 100 gm of the mixture contains 20 g of hydrogen, therefore 80 g of the mixture will be oxygen.

No. of moles of hydrogen =

mol. wt.

wt.

=

2

20

=10 moles

No. of moles of oxygen =

Mol. wt.

wt.

=

32

80

=2.5 moles

∴ Mole fraction of hydrogen (X

hydrogen

)=

Total no. of moles

Moles of hydrogen

=

12.5

10

=0.8

As we know that

Partial pressure = mole fraction × pure pressure

Given that Pure pressure =1 bar

∴ Partial pressure of hydrogen =X

hydrohen

×P

⇒P

hydrogen

=0.8×1=0.8 bar

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