Question

A mixture of ideal gases has 1 mole of Ne.
2 moles of Nitrogen , and 3 moles of ozone at absolute
temperature T. The internal energy of the mixture​

Answer 1

Answer:

Ne is monoatomic gas U= 3/2RT

N2 is diatomic gas U=5/2RT

O3 is non linear triatomic =6/2RT

Ne+N2+O3 = 3/2RT+5/2RT+6/2RT

=31/2RT

Explanation:

Answer 2

Answer:

31RT/2

Explanation:

for Ne,mono atomic-3/2RT

N2-diatomic gas-5/2RT

O3-nonlinear triatomic-6/2RT

so we add these then we get. 31RT/2