Question

A mixture of KOH and Na2CO3 solution required 15ml of N/20 HCl using phenolphthalein as indicator .The same amount of alkali mixture when titrated using methyl orange as an indicator required 25ml of same acid.Calculate the amount of KOH and Na2CO3 present in solution.

Answer 1

25ml of each in soln are present

Answer 2

Answer:

Explanation:

as phenolpthalein is used so valency factor of na2co3 = 1

equivalent of  koh + equivalent of na2co3 = 0.75

moles of koh + moles of na2co3 = 0.00075

when titrated with methyl orange

equivalent of koh + equivalent of na2co3 = 1.25

moles of koh + 2 moles of na2co3 = 0.00125

moles of na2co3 = 0.00050

moles of koh = 0.00025

mass of na2o3 = 0.05

mass of koh=0.014

mass of solution = 0.064