A mixture of milk and water is kept in a container in the ratio of 14:3.now 51 litres of the mixture is taken out from the container and 5 litres of pure water and 10 litres of pure milk are added to the mixture.id the resultant mixture contains 25 percentage water,then what was the initial mixture in the container?
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Answer:
68 lit
Step-by-step explanation:
Quantity of milk in the vessel = 14x litres
Quantity of water = 3xlitres
In 25.5 litres of mixture , Milk = 14171417 x 25.5 = 21 litres
water = 4.5 litres
After respective additions in the resulting mixture water = 3x - 4.5 +2.5
=(3x-2)litres
Quantity of mixture = 17x-25.5+7.5
=(17x-18)litres
According to the question ,
3x−217x−183x−217x−18 = 2010020100 = 1515
=>17x-18 =15x-10
=>17x-15x=18-10
2x=8=>x=4
Initial quantity of the mixture =17x=17X4=68 litres
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