A mixture of N2 and H2 is caused to react in a
closed container to form NH3. The reaction ceases
before either reactant has been totally consumed.
At this stage, 2 moles each of N2, H2 and NH3
are present. Then the weight of N2 and H2 present
originally were respectively
Answers
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N2+3H2⇌2NH3
Initially moles A B 0
At eq−b A−x B−x 2x
2x=2⇒x=1
A−x=2⇒A−1=2⇒A=3
B−3x=2⇒B−3=2,⇒B=5
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