Question

A mixture of NH; and ND,
heated in a closed vessel
until equilibrium is reached.
The scrambling of atom
produces different species in
vessel, when this equilibrium
mix is allowed to escape
through a pinhole, ratio of
rates of diffusion of lightest
to heaviest gases is

Answer 1

Answer:

Explanation: please check the attachment to get solution

Answer 2

The correct answer will be "√10 : 1".

Explanation:

The equation will be:

NH₃ + 3/2 D₃  →  ND₃+ 3/2 H₂

Lightest gas here seems to be H₂ as well as the hardest gas becomes ND₃.

As we know,

⇒  $r \ \alpha \sqrt{\frac{1}{m}}$

Now,

$\frac{r \ H_{2}}{r \ ND_{3}} = \sqrt{\frac{MND_{3}}{MH_{2}}$

⇒       $=\sqrt{\frac{20}{2} }$

⇒       $=\sqrt{10}:1$

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https://brainly.in/question/17656263