Question

A mixture of nitrogen and hydrogen gas has
density 0.505x10-'g cm' at 293 K and 750 mm
Hg pressure. What per cent of the mass is
nitrogen?​

Answer 1

Answer:

We know that PV = n RT= (m/M) RT .

M= dRT /P  (Since m/V = density d).

=0.505 x .0821 x 293/ 750 /760 = 12.30gmol-1 .

Let x be the mass fraction of N2 and (1- x) is the mass fraction of H2.

So, x * 28 + (1- x)* 2 = 12.30

26 x = 10.30.

x = 0.39.

% Composition of N2 = 39 % .

% Composition of O2 = 61%.